In a mass spectrometer, a singly ionized 24Mg ion has a mass equal to 3.983 10-26 kg and is accelerated through a 3.00-kV potential difference. It then enters a region where it is deflected by a magnetic field of 526 G. Find the radius of curvature of the ion's orbit. Note: There are 10,000 G in 1 T and 1,000 V in 1 kV.

The radius of curvature of the ion's orbit is 0.59 meters

Explanation:

Given that,

Mass of the 24 Mg ion,

Potential difference, V = 3 kV

Magnetic field, B = 526 G

Charge on single ionized ion,

The radius of the the path traveled  by the charge is circular. Its radius is given by :

v is speed of particle.

v can be calculated using conservation of energy as :

Radius,

So, the radius of curvature of the ion's orbit is 0.59 meters.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: