The pressure is measured at the bottom of a cylindrical container with cross-sectional area A that is filled to a height H by a liquid with density rhoL . A cube of volume Vc and density rhoc is placed in the liquid and floats partially submerged, causing a change Δh in the height of the liquid. As a result, the pressure at the bottom of the container increases. (a) In a coherent, paragraph-length response, describe the relevant forces acting on the cube and the liquid, and explain how they result in the increase in pressure at the bottom of the container.

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

number of electrons for neutral cl

no simpler subs form complex ones. synthesise = make