Stunt car A and stunt car B are identical cars with the same mass of 43.3 kg. They are both traveling at 70.7 m/s. Stunt car A crashes into a hard wood wall, whereas stunt car B crashes into a large pile of soft sand. They both come to a complete stop after the impact.

Stunt Car A experiences a over a of time. Stunt Car B experiences a over a of time. Because of the force experienced by Stunt Car A, it will sustain damage than Stunt Car B.

1) Stunt car A experiences a large stopping force over a short period of time.

2 stunt car B experiences a small stopping force over a longer period of time

3) stunt car A will sustain more damage than stunt car B

Explanation:

the mass and speed of both stunt cars are equal.

Mass = 43.3kg

Speed = 70.7 m/s

Their initial momentum = mv = 43.3 x 70.7 = 3061.31 kg-m/s

Their final momentum will be equal to zero since they come to a complete stop.

The rate of change of momentum = 3061.31 - 0 = 3061.31 kg-m/s

Rate of change of momentum = impulse

Impulse = force times time duration of impact

I = f x t

From this equation, the answers it can be seen that a shorter time duration of impact will produce a large force and vice versa.

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