A spacecraft is separated into two parts by detonating the explosive bolts that hold them together. The masses of the parts are 1200 kg and 1800kg; the magnitude of the impulse on each par from the bolts is 300 N s. With what relative speed do the twe twe parts separate because of the detonation?

Explanation:

Given that,

A space ship is separated into two part

Mass of first part

M1 = 1200kg

Mass of second part

M2 = 1800kg

Magnitude of impulse on each part is

I = 300Ns

We want to find the relative velocity at which the two parts separate

Now,

Impulse is give as

I = ft = mv - mu

Since the body is considered to be at rest before detonation

Then, I = mv

So for first part

I = M1•V1

V1 = I / M1

V1 = 300 / 1200

V1 = 0.25m/s

Also, for second part

V2 = —I / M2

V2 = —300 / 1800

V2 = —0.167 m/s

NOTE: the negative sign is due to the fact that the two bodies are moving away from each other.

The relative speed of the two masses because of detonation is

V = V1 — V2

V = 0.25 — (—0.167)

V = 0.25 + 0.167

V = 0.417 m/s

The relative speed of the two masses because of detonation is 0.417 m/s

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

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