Enter the measured values of the angles of incidence and refraction below. Angle of incidence θi = 76.5 Correct: Your answer is correct. Your value is acceptable.° Angle of refraction θr = 76.5 Incorrect: Your answer is incorrect. Your value is too high.° Calculate the index of refraction using Snell's Law and the measured values of the angles of incidence and refraction. nacrylic = The accepted value of the index of refraction for acrylic is 1.49. What is the percent error between the accepted value and the experimental value of n? Hint Percent error = %

Explanation:

Given that the inputted angle of incidence is accepted

Angle of incidence θi = 76.5°

But angle of refraction is not acceptable

Angle of refraction θr = 76.5°

We are told that the value is too high

Then, θr < 76.5°

We want to calculate index of refraction n?

The acceptable value of refraction index of acrylic is 1.49

So the true value is 1.49

So, let calculate the measure value

Refractive index is given as

n = Sin(i) / Sin(r)

Then,

n = Sin(76.5) / Sin(76.5)

Then, n = 1

Now, percentage error of the refractive index,

Percentage error is

%error= |true value—measure value| / true value × 100

The true value is 1.49

The measure value is 1

Then,

%error = ( |1.49—1| / 1.49 ) × 100

% error = ( 0.49 / 1.49 ) × 100

%error = 0.3289 × 100

%error = 32.89%