Write the equation of a wave traveling along the +x-axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330m/s.

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

Explanation:

Given data

Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s

The equation  format is written as,

y =   A   sin (       k        x  –   ω     t)

We need the value of  A, k, x -ω t

1. Find the k value

v     =  f ×λ

330 = 440×λ

   k = 2π×λ

k = 880 π /330  m-1

440 ×2π = w

2. Find the ω  value

f×2π =ω

ω = 880 π  s-1

3. Find the A value

we get A value from the given data

A = 0.02 m

By the formula,

y =   A   sin (       k        x  –   ω     t)

Substitute the values we get the equation,

y = 0.02 sin (880π/330 x – 880 πt)

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

b.

explanation:

10.0