While dragging a crate a workman exerts a force of 628 n. later, the mass of the crate is increased by a factor of 3.8. if the workman exerts the same force, how does the new acceleration compare to the old acceleration?

Force applied = F = 628 N 
Acceleration = a m/s² 
Newton's 2nd law of motion : F = Ma 
 a = F/M (1) 
New mass of the crate = M1 = 3.8M kg 
New acceleration = a1 = F/M1 = F/(3.8 M) (2) 
a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 Answer

The answer is b hope this