A copper container of mass 84 g contains 84 g of water at 10 °C.46 g of water at 100 °C is mixed with the water in the copper container. What is the final temperature of the water?
(Specific heat capacity of water
= 4 200 J kg- °C, specific heat
capacity of copper = 400 J kg-1 °C-))

A 10 °C
30 °C
B 20 °C
D 40 °C

No because scientist are still changing there mines today so they are not correct to this day

Ithink the answer would be a 

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !