Alculate the first and second velocities of the car with three washers attached to the pulley, using the formulas

v1 = 0.25 m / t1, and

v2 = 0.25 m / (t2 – t1)

where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.

What is the first velocity of the car with three washers at the 0.25 meter mark?

2.23
⇒ 0.19 m/s

What is the second velocity of the car with three washers at the 0.50 meter mark?

3.13
⇒ 0.45 m/s

Use the formula dude someone’s bro’s he iss

Answerinternal combustion engine fuel;

To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.