Physics, 18.04.2020 02:43 giovannymarvez16
A solid sphere of radius R is placed at a height of 30 cm on a15 degree slope. It is released and rolls, without slipping, to the bottom.
a) From what height should a circular hoop of radius R bereleased on the same slope in order to equal the sphere's speed atthe bottom?
b) Can a circular hoop of different diameter be released froma height of 30 cm and match the sphere's speed at the bottom? If, so what is the diameter? If not, why not?
Answers: 2
is mathematically represented as 
![mgh_s = \frac{1}{2} [\frac{2}{5} mr^2 ][\frac{v}{r} ]^2 + \frac{1}{2}mv^2](/tpl/images/0609/8612/98b2d.png)
![mgh_s = \frac{1}{2} mv^2 [\frac{2}{5} +1 ]](/tpl/images/0609/8612/7192f.png)
![mgh_s = \frac{1}{2} mv^2 [\frac{7}{5} ]](/tpl/images/0609/8612/39d5d.png)
![gh_s =[\frac{7}{10} ] v^2](/tpl/images/0609/8612/ce811.png)
![mgh_c = \frac{1}{2} (mr^2)[\frac{v}{r} ] ^2 + \frac{1}{2} mv^2](/tpl/images/0609/8612/6b558.png)
is the height where the circular hoop would be released to equal the speed of the sphere at the bottom
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A solid sphere of radius R is placed at a height of 30 cm on a15 degree slope. It is released and ro...
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