A ball mass m is launched up a semicircular in a way that at the top of the chute, just before free fall, the ball has a centripetal acceleration of magnitude 6g. If the bottom of the chute is defined to be the height where the gravitational PE is 0 the moment the ball leaves the chute what is the mechanical energy?

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

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