A 15-g 10-cm-long wire is suspended horizontally between the poles of a horseshoe magnet. The magnetic field is horizontal between the poles of the magnet where the wire is suspended. When the 0.50-A current in the wire is turned on, the wire jumps up and out of the magnet. Draw the situation, carefully indicating the direction of the current and the field. What is the minimum magnetic field created by the horseshoe magnet?

The answer is b.the gaseous state is electrically positive, while the plasma state is electrically negative. 

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.