Two identical silver spheres of mass m and radius r are placed at different distances from the sun. Sphere 1 is placed at a distance R and sphere 2 is placed at a distance 2R. The ratio of the pressure of solar radiation on sphere 2 to that on sphere 1 is:

The rearrangement of particles in a physical change. hope this

Pe = 1/2k(x)^2  and .05n/m = .05x10^-9m = x 

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

Wow good luck with that answer