What is the focal length of a lens that will form an image on the wall that is twice the size of the lightbulb?

88.89 cm

Explanation:

We are given that

Distance between bulb and wall=4 m=

1 m=100 cm

Let  h be  the height of object

Object distance=-u

Image distance= v

Height  of object=2h

Magnification=

Lens formula

the bal will not change its velocity.

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