A 0.134-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find the time rate of change of electric flux between the plates. V·m/s (b) Find the displacement current between the plates. A

a) 1.51Vm/s

b)Id=0.134A

Explanation:

(a) The time rate of change of electric flux between the plates can be computed by using:

where Ic is the current of the capacitor, e0 is the dielectric permittivity of vacuum and A is the area of the capacitor.

(b) The displacement current coincides with capacitor current:

Id = 0.134A

hope this helps!!

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explanation:

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