The only force acting on a 3.1 kg canister that is moving in an xy plane has a magnitude of 2.6 N. The canister initially has a velocity of 2.3 m/s in the positive x direction, and some time later has a velocity of 6.4 m/s in the positive y direction. How much work is done on the canister by the 2.6 N force during this time?

55.29 J

Explanation:

mass of canister, m = 3.1 kg

magnitude of force, F = 2.6 N

initial velocity, u = 2.3 m/s

final velocity, v = 6.4 m/s

Let W is the work done.

According to the work energy theorem, the work done by all forces is equal to he change in kinetic energy.

here F is the only force acting on the canister.

initial kinetic energy, k = 0.5 x m x u²

k = 0.5 x 3.1 x 2.3 x 2.3 = 8.1995 J

final kinetic energy, k' = 0.5 x m x v²

k' = 0.5 x 3.1 x 6.4 x 6.4 = 63.488 J

So, the change in  kinetic energy,

Δk = k' - k

Δk = 63.488 - 8.1995 = 55.29 J

Thus, the work done by the force is 55.29 J.

the part of the wave he is travelling on is the crest

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.