Physics, 16.04.2020 02:21 kimbllumi

A 0.60 kg spike is hammered into a railroad

tie. The initial speed of the spike is equal to

1.8 m/s.

If the tie and spike together absorb 57.8

percent of the spike's initial kinetic energy

as internal energy, calculate the increase in

internal energy of the tie and spike.

Answer in units of J.

Answers: 2

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Answers

A 0.60 kg spike is hammered into a railroad tie. The initial speed of the spike is equal to 1.8 m/s. If the tie and spike together absorb 57.8 percent of the spike’s initial kinetic energy as internal energy, calculate the increase in internal energy of the tie and spike. Answer in units of J.

Change in internal energy of the tie and the spike is 0.56 Joules (J).

Explanation:

Given:

Mass of the spike, m = 0.60 kg

Its initial speed, u = 1.8 m/s

According to the question:

The tie and spike together absorb 57.8 percent of the spike’s initial kinetic energy as internal energy.

We have to find the increase in internal energy of the tie and spike.

So,

Let the change in internal energy = ΔE

And the kinetic energy is KE :

Then,

⇒ $KE=\frac{mu^2}{2}$

⇒ $KE=\frac{0.60\times (1.8)^2}{2}$

⇒ $KE=\frac{0.60\times 3.24}{2}$

⇒ $KE=\frac{1.944}{2}$

⇒ KE= 0.972 J

Now,

Change in internal energy:

⇒ $\triangle E = 0.578\times KE$ ...as 57.8 % = 0.578

⇒ $\triangle E = 0.578\times 0.972$

⇒ $\triangle E = 0.561816$ J

Change in internal energy of the tie and the spike is 0.56 Joules.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

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A 0.60 kg spike is hammered into a railroad

tie. The initial speed of the spike is equal...

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