A square loop of side length a =4.5 cm is placed a distance b = 1.1 cm from a long wire carrying a current that varies with time at a constant rate, i. e. I(t) = Qt, where Q = 5.9 A/s is a constant. In what direction does this current flow?
Part (b) What is the magnitude of the flux through the loop? Select the correct expression Correct Part (c) If the loop has a resistance of 2.5 Ω, how much induced current flows in the loop

a) The current will flow in a clockwise direction

b) The magnitude of the flux through the loop is given by the equation ;

c) The amount of the induced current that flows in the loop =

Explanation:

The magnitude of the flux through the loop is given by the equation ;

The amount of the induced current that flows in the loop can be calculated as:

Emf induced  

The current induced

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hope this : d

higher potential

explanation:

because it is in a high speed so it must move into a of high potential