As Halley's comet orbits the sun, its distance from the sun changes dramatically from 8.8 x 1010 m to 5.2 x 1012 m. if the comet's speed at closest approach is 5.4 x 104 m/s, what is its linear speed when it is farthest from the sun, if angular momentum is conserved

The linear speed when it is farthest point is 913.85 m/s

Explanation:

Given:

rp = radius at nearest point = 8.8x10¹⁰ m

ra = radius at farthest point = 5.2x10¹² m

vp = velocity nearest point = 5.4x10⁴m/s

The angular momentum is conserved, thus:

La = Lp

b

explanation:

bc its just b

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2