To practice Problem-Solving Strategy 6.1 Work and Kinetic Energy. Your cat Goldie (mass 8.50 kg ) is trying to make it to the top of a frictionless ramp 39.930 m long and inclined 27.0 ∘ above the horizontal. Since Goldie can’t get any traction on the ramp, you push her up the entire length of the ramp by exerting a constant 37.40 N force parallel to the ramp (there is a set of stairs alongside the frictionless ramp on which you can walk). If Goldie is moving at 2.000 m/s at the bottom of the ramp (assume she has gotten a running start), what is her speed when she reaches the top of the incline?

Explanation:

the forces parallel to the ramp are:

where F is the force exerted by the person, Mg is the weight of the cat, theta is the angle of the ramp, m is the mass of the cat and a is the acceleration.

By replacing we can obtain the acceleration of the cat:

Then, the cat is slowing down while it is going up the ramp.

Now, we can compute the final speed by using the following formula:

!!! the cat has a negative acceleration, hence, the force exerted by the person is not enough to move the cat upward.

it is neccesary to review the values of the exercise

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

6 cos 34, 6 sin 34 trig