A brass rod is .500 m long at 20.0celsius. what is the length of the rod if it is heated to 50.0 celsius

L' = 0.5002535 [m]

Explanation:

This is a characteristic problem of material mechanics, which includes deformation of an element by temperature increase.

In order to solve this problem, we need the value called the coefficient of thermal expansion and the use of the following expression:

DL = α*(DT)*L

where:

DL = Length change [m]

α = coefficient of thermal expansion [1/°C]

DT = Temperature change [°C]

L = Original length [m]

For copper or brass rod the α = 16.9*10^-(6) [1/°C]

DL = 16.9*10^-(6)*(50-20)*0.5

DL = 2.535*10^(-4) [m] = 0.0002535 [m]

The new length is:

L' = DL + L = 0.0002535 + 0.5 = 0.5002535 [m]

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

ice to water 1 water to vapour 2 latent heat