The emf of a battery is 12 volts. When the battery delivers a steady current of 0.5 ampere to a load, the potential difference between the terminals of the battery is 10 volts. What terminal voltage would you expect if the battery were connected to a load with less resistance?

The terminal voltage would increase to be > 10 V

Explanation:

Battery emf = 12 volt

Potential difference at 0.5 ampere load in between the terminals is 10 volts

The formula for terminal voltage is

V = emf - IR

Where:

I = Current = 0.5 A

R = Resistance

Therefore, when V = 10 volt, we have

10 V = 12 V - 0.5 × R₁

∴ R₁ = 4 Ω

When the resistance of the load is lower say R₂ < R₁, then we have

V₂ = 12 V - 0.5 × R₁ = 12 V - 0.5 × R₂ < R₁

= 12 V -<0.5 × R₁

Since V₁ = 12 V - 0.5 × R₁

V₂ > V₁ and the terminal voltage would increase.

V₂ > 10 V.

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50