Two charges of magnitude +q are separated by a distance d. Assuming there are no changes to anything else, but the charges are separated by 3 times their current distance, what will happen to the Coloumb force between them? (1 point)

The Coulomb force between them will decrease by a factor of 1/9

Explanation:

The Coulomb's force acting between two particles of equal charge, q, separated by a distance, d, is given as:

where k = Coulomb's constant

If they are separated by 3 times their current distance, the new distance becomes 3d. Hence, the Coulomb force acting between them becomes:

Hence, the Coulomb force decreases by a factor of 1/9.

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explanation:

inverse v=i*r

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