A hollow cylinder of mass 2.00 kgkg, inner radius 0.100 mm, and outer radius 0.200 mm is free to rotate without friction around a horizontal shaft of radius 0.100 mm along the axis of the cylinder. You wrap a light, nonstretching cable around the cylinder and tie the free end to a 0.500 kgkg block of cheese. You release the cheese from rest a distance hh above the floor. If the cheese is moving downward at 4.00 m/sm/s just before it hits the ground, what is the value of hh? Express your answer with the appropriate units.

The value of h is 2.86 m

Explanation:

Applying the energy conservation:

Where

m = 2 kg

R₁ = 0.2 m

R₂ = 0.1 m

The angular speed is:

w = v/R₂ = 4/0.2 = 20 rad/s

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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