An automobile of mass 1900 kg is supported by a hydraulic lift having a large piston of cross-sectional area 10 m 2. The mechanic has a foot pedal attached to a small piston of cross-sectional area 0.5 m2. What force in Newtons must be applied to the small piston to raise the automobile

The force must be applied to the small piston to raise the automobile = 932 N

Explanation:

Given data

Mass = 1900 kg

Force = m g

Force = 1900 × 9.81 = 18639 N

Area of larger Piston = 10

Area of smaller Piston = 0.5

Force on smaller piston =

From the equilibrium

Pressure on larger piston = Pressure on smaller piston

= 932 N

Therefore the force must be applied to the small piston to raise the automobile.

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