Consider helium at 350 K and 0.75 m3/kg. Using Eq. 12-3, determine the change in pressure corresponding to an increase of (a) 1 percent in temperature at constant specific volume, (b) 1 percent in specific volume at constant temperature, and (c) 1 percent in both the temperature and specific volume.

a)

b)

c) dP = 0 Pa

Explanation:

The specifies equation is :

Note that:

1% increase in temperature at specific volume:

a) Change in pressure of helium at constant volume:

R = 2.0769 kJ/kg-K

dT = 3.5 K

v = 0.75 m³/kg

b)

dv = (1%/100%) *0.75

dv = 0.0075 m³/kg

Change in pressure of helium at constant temperature:

R = 2.0769 kJ/kg-K

T = 350 K

v = 0.75 m³/kg

dv = 0.0075 m³/kg

c) The change in pressure of helium :

dP = 9.692 - 9.692

dP = 0

this would be about 43%

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