A particle with a charge of −1.7 μC and a mass of 3.0 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 43 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.

Explanation:

We are given that

Mass,m=

Speed,v=43 m/s

We have to find the potential difference between A and B.

By law of conservation of energy

Kinetic energy=Potential energy

Substitute the values

Negative charge is always accelerated towards  high potential.Therefore,potential at point B is higher than the potential at point A.

Hence,

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.