The average intensity of light emerging from a polarizing sheet is 0.764 W/m^2, and the average intensity of the horizontally polarized light incident on the sheet is 0.883 W/m^2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

The angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

Explanation:

Given;

average intensity of incident light, I = 0.764 W/m²

average intensity of transmitted light, I₀ = 0.883 W/m²

I = I₀Cos²θ

where;

θ is the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Cos²θ = I / I₀

Cos²θ = 0.764/0.883

Cos²θ = 0.8652

Cosθ = √0.8652

Cosθ = 0.9301

θ = Cos⁻¹ 0.9301

θ = 21.55⁰

Therefore, the angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

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