In two-photon ionization spectroscopy, the combined energy of two different photons is used to remove an electron from an atom or molecule. In such an experiment, a potassium atom in the gas phase is ionized by two different lasers, one of which has a wavelength of 770.0 nm. What is the maximum wavelength for the second laser that will cause two-photon ionization? The ionization energy of potassium is 6.96E-19 J. nm

The maximum wavelength of second laser is 453.8 nm

Explanation:

Given:

Wavelength of light m

Ionization energy of potassium J

First find the energy related to the one of light,

Where ,

    J

This is the energy of the first laser, the missing energy is given by.

   J

For finding wavelength of second laser,

    m

    nm

Therefore, the maximum wavelength of second laser is 453.8 nm

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jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.