A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds into the wood block such that the collision is perfectly inelastic. Use conservation of momentum to find the speed of the wooden block (with bullet embedded) at the instant after the collision.

The value of speed of wooden block at the instant after the collision   262.41  

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet = 266

Final velocity of whole system is

Put all the values in above formula we get

262.41  

This is the value of speed of wooden block at the instant after the collision.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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