Calculate the wavelength λ and the frequency f of the photons that have an energy of E photon = 2.32 × 10 − 19 J. Ephoton=2.32×10−19 J. Use c = 3.00 × 10 8 m/s c=3.00×108 m/s for the speed of light in a vacuum.

Frequency =3.5×10^14hertz

Wavelength = 8.6×20^-7m

Explanation:

Energy of photon is expressed as;

E = hf where;

h is the Planck constant

f is the frequency of the photons

From the formula f = E/h

Given E = 2.32 × 10^ − 19 J

h = 6.63×10^-34Js

f = 2.32×10^-19/6.63×10^-34

f = 0.35×10^(-19+34)

f = 0.35 × 10^15

f = 3.5×10^14hertz

To get the wavelength, we will use the relationship:

f = c/λ

λ = c/f

Given c = 3×10^8m/s

f = 3.5×10^14hertz

λ = 3×10^8/3.5×10^14

λ = 0.86×10^-6m

λ = 8.6×20^-7m

i guess it’s a and b

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