A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A.

(a) Calculate the energy density of the magnetic field inside the solenoid.
(b) Find the total energy in joules stored in the magnetic field there (neglect end effects).

(a) Energy density will be equal to

(b) Total energy will be equal to 0.0718 J

Explanation:

It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to

(b) Total energy stored in magnetic field

(a) Energy density will be equal to

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

i think the answer would be b