Three small masses are positioned at the following coordinates: 3.0 kg at (3.0 m, 2.0 m); 4.0 kg at (0.0 m, -1.0 m); and 5.0 kg at (5.0 m, -7.0 m). What are the coordinates of the center of mass (or center of gravity) of this system?

(x,y)=(2.7m,-2.75m)

Explanation:

Given m1=3kg,x1=3m,y1=2m,m2=4kg,x2=0m,Y2=-1,m3=5kg,x3=5kg,y3=-7m

Hence coordinate for centre of mass (x,y)

X=[m1X1+m2X2+M3X3/m1+m2+m3)

3*3+4*0+5*5/3+4+5

=9+0+25/12=34/12=2.8m

Y=(m1*y1+m2*y2+m3*y3/m1+m2+m3)

Y=(3*2+4*-1+5*-7/3+4+5)

Y=(6-4-35/12)=-2.75m

none, its a machine

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever