A block of mass m = 12.0 kg and speed V and is behind a block of mass M = 26.0 kg and speed of 0.50 m/s as shown in the figure. The surface is frictionless, and the blocks suddenly collide and couple. After the collision, the blocks have a common speed of 0.90 m/s. How much kinetic energy of the blocks is lost due to the collision? Hint: Use conservation of momentum to calculate the missing speed and then calculate the kinetic energy of both objects before the collision and then the kinetic energy of both objects after.