Suppose you push a hockey puck of mass mm across frictionless ice for a time ΔtΔt, starting from rest, giving the puck speed vv after traveling distance dd. If you repeat the experiment with a puck of mass 2mm, 1. How long will you have to push for the puck to reach the samespeed v?t/ (delta t) = ? 2.How long will you have to push for the puck to travel the samedistance d?t/ (delta t) = ?

My answer is opptionc, just check with anyone else

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.