A hollow spherical shell has mass 8.05kg and radius 0.215m . It is initially at rest and then rotates about a stationary axis that lies along a diameter with a constant acceleration of 0.895rad/s2 .

What is the kinetic energy of the shell after it has turned through 5.25rev ?

Express your answer with the appropriate units.

The kinetic energy of the shell after it has turned through 5.25rev is 7.32J

Explanation: Please see the attachments below

930.21J

Explanation:

The kinetic energy of a solid body that is rotating, is given  by:

where I is the moment of inertia and w is the angular velocity.

The moment of inertia for a spherical shell is:

where M is the mass and R is the radius of the sphere. By replacing we have

To calculate w we have to use the equation

where we have taken w0=0 rad/s.

Finally, by replacing I and w we obtain:

HOPE THIS HELPS!

the force required to move the cart is divided by three or 33.33 n.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s