Three resistors with the values of R_1, R_2, and R_3 are connected in parallel. Which of the following expresses the total resistance e, R_eq of the resistors?
a.) R_eq = R_1 + R_2 + R_3
b.) R_eq = (1/R_1 + 1/R_2 + 1/R_3)
c.) R_eq = R_1 = R_2 = R_3
d.) R_eq = (1/R_1 + 1/R_2 + 1/R_3 ) ^-1

Option d.)

R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Explanation:

Since, there are three resistors connected in parallel, the reciprocal of the total resistance of the resistor combination (R_eq) is obtained by adding the reciprocal of each resistance.

i.e 1/R_eq = (1/R_1 + 1/R_2 + 1/R_3)

So, R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Thus, the total resistance (R_eq) is equal to the inverse of the sum of the reciprocal of each resistance.

double the distance = divide strength by 4

see earlier