Two cars traveled equal distances in different amounts of time. car a traveled the distance in 2.4 h, and car b traveled the distance in 4 h. car a traveled 22 mph faster than car b. how fast did car a

We let x the distance traveled by Car A and y the distance traveled by car B. The speed of car A can be represented as x/2.4 and for Car B is y/4. From the statement given, we can write an equation relating the speed of both cars.

x/2.4 = 22 + y/4

Since y = x, then:

x/2.4 = 22 + x/4

Solving for x, we obtain:

x= 132 meters traveled by both cars

Therefore, Car A has a speed of 55 mph.