A jack in the box is built around with a spring constant of 70N/m. How much hard does the spring push when you compress it from 40 cm long down to 15 cm long?

17.5N

Explanation:

Given that,

spring constant (k) = 70N/m

Original length (lo) = 40 cm

New length (ln) = 15 cm

extension of spring (e) = new length - original length

i.e e = ln - lo

e = 15 cm - 40 cm

e = -25cm (the negative sign is negligible, just the same magnitude matters)

So, convert 25cm to metres

If 100cm = 1m

25cm = 25/100 = 0.25m

(Note that how hard the spring push refers to the Force, hence, find force.)

Now, apply the Hooke law (F = ke)

Force = spring constant x extension

F = 70N/m x 0.25m

F = 17.5N

Thus, the spring push with a force of 17.5N when compressed.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force