⚠️⚠️A driver brakes to stop a car in 3.0 s. The car's momentum was 33,000
kg m/s when the braking began. What magnitude of force was used to
stop the car?*
33,000N, 11,000N, 99,000N, 0.11N

11000 N

Explanation:

Given that,

Time required to stop car = 3.0 s

The car's momentum = 33,000

kg m/s

magnitude of force = ?

Recall that impulse is equal to the change in momentum of the car, hence

Impulse (I) = Momentum

(Since I = force x time, then

Force x time = momentum)

F x 3.0 s = 33,000 kg m/s

F = 33,000kg m/s / 3.0s

F = 11,000 N

Thus, 11000N of force was used to stop the car.

f=ma newton's second law 7x8=56n