A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.00629 T and the proton's velocity makes an angle of 137 ∘ with the field, what is the magnitude of the magnetic force acting on the proton?

Force on the proton will be

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light

So speed of proton

Magnetic field B = 0.00629 T

Charge on proton

Angle between velocity and magnetic field

Force on the proton is equal to

overcharge is the right answer system

i think it's 35 meters