A particle moving along a straight line with uniform acceleration

describes 1.45 m and 1.85 m in the sixth and the tenth second

respectively. What distance will it cover in the sixteenth second?

volts times amps 6 x 0.5 3w

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation