Physics, 08.04.2020 01:53 nathrontheking
A fluid, with a density of rho = 1165 kg/m3, flows in a horizontal pipe. In one segment of the pipe the flow speed is v1 = 4.53 m/s. In a second segment the flow speed is v2 = 1.77 m/s. What is the difference between the pressure in the second segment (P2) and the pressure in the first segment (P1)?
Answers: 3
Pa
![P_{2} - P_{1} = \frac{1}{2} \times 1165 \times[ (4.53)^{2}- (1.77)^{2}]](/tpl/images/0588/5134/84c66.png)
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A fluid, with a density of rho = 1165 kg/m3, flows in a horizontal pipe. In one segment of the pipe...
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