A loop of wire carries a conventional current of 0.9 amperes. The radius of the loop is 0.05 m. Calculate the magnitude of the magnetic field at a distance of 0.46 m along the axis of the loop, from the center of the loop. B

0.098 T

Explanation:

Parameters given:

Current in the wire, I = 0.9 A

Radius of loop, r = 0.05 m

Distance of the point of consideration, L = 0.46 m

The magnetic field, B, at distance, L, due to a current, I, flowing in a wire of radius, r, is given as:

B = (N*r*I) / L

Where N = number of turns in the loop = 1

Therefore, B is:

B = (1 * 0.05 * 0.9) / 0.46

B = 0.098 T

The magnetic field, B is 0.098 T

explanation:

newton's third law, for every action there is an equal and opposite reaction.

c. newton's third law of motion