A bullet of mass 2.6 g strikes a ballistic pendulum of mass 3.6 kg. The center of mass of the pendulum rises a vertical distance of 13 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

2211.4 m/s

Explanation:

We are given that

Mass of bullet,m=2.6 g=

1 kg=

Mass of pendulum,M=3.6 kg

Vertical distance,y=13 cm=

1 m=100 cm

We have to find the bullet's initial speed.

Kinetic energy of bullet=P.E

Where

According to law of conservation of momentum

Hence, the bullet's initial speed=2211.4 m/s

answer; i believe the correct answer is (40,000 j) good luck

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