A circular coil that has N = 290 N=290 turns and a radius of r = 11.5 cm r=11.5 cm lies in a magnetic field that has a magnitude of B 0 = 0.0705 T B0=0.0705 T directed perpendicular to the plane of the coil. What is the magnitude of the magnetic flux Φ B ΦB through the coil?

The magnitude of magnetic flux is 0.849 Wb.                

Explanation:

Given that,

Number of turns in a coil, N = 290

Radius of the coil, r = 11.5 cm    

Magnetic field, B = 0.0705 T

The magnetic field is directed perpendicular to the plane of the coil. The magnetic flux is given by :

So, the magnitude of magnetic flux is 0.849 Wb.                                                              

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form