An electric generator contains a coil of 130 turns of wire, each forming a rectangular loop 74.6 cm by 24.9 cm. The coil is placed entirely in a uniform magnetic field with magnitude B = 3.82 T and initially perpendicular to the coil's plane. What is in volts the maximum value of the emf produced when the loop is spun at 1120 rev/min about an axis perpendicular to the magnetic field?

10.85 kV

Explanation:    

The maximum value of the emf (ε) produced can be calculated using Faraday's law equation:

  (1)

Where:

N: is the turns of wire = 130 turns

Φ: is the magnetic flux = BAcos(θ)

B: is the magnetic field = 3.82 T

A: is the area of the coil = a*b = 0.746 m*0.249 m = 0.186 m²

θ: is the angle between the magnetic field lines and the normal to A = ωt = 2πft

f: is the frequency = 1120 rev/min = 18.7 rev/s    

From equation (1) we have:

Therefore, the maximum value of the emf produced is 10.85 kV.

I hope it helps you!  

The maximum value of the emf produced is 10819.098 V

Explanation:

Given data:

N = number of turn = 130

The area is:

B = magnetic field = 3.82 T

w = angular speed = 1120 rev/min = 117.286 rad/s

The maximum value of the emf produced is:

if the forces acting on an object are unbalanced, the object will accelerate in the direction of the net force on the object.

explanation:

this is best explained by having an understanding of newton's second law, which states that f=ma. you see, when the forces are unbalanced, net force (sum of all forces) is not zero. therefore making it necessary for the object to have an acceleration in the direction of the net force.

the answer would be c