Kramer goes bowling and decides to employ the force of gravity to "pick up a spare." He rolls the 7.0-kg bowling ball very slowly so that it comes to rest a center-to-center distance of 0.10 m from the one remaining 1.5-kg bowling pin. 1) Determine the force of gravity between the ball and the pin and comment on the efficacy of the technique. Treat the ball and pin as point objects for this problem. (Express your answer to two significant figures.) nN

70.035nN

Explanation:

M₁ = 7.0kg

m₂ = 1.5kg

r = 0.1m

G = 6.67*10⁻¹¹ Nm²/kg

Gravitational force (F) of an object is directly proportional to the product masses and inversely proportional to the square of their distance apart.

F = GM₁M₂ / r²

F = (6.67*10^-11 * 7.0 * 1.5) / (0.1)²

F = 7.0035*10^-10 / 0.01

F = 7.0035 * 10^-8 N

F = 70.035nN

The gravitational force acting on the bowling ball is 70.035nN.

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