Billiard ball A, mass 0.17 kg, moving due east with a velocity of 4.0 m/s, strikes stationary billiard ball B, also mass of 0.17 kg. After the collision, ball A moves off at an angle of 30° north of east with a velocity of 3.5 m/s, and ball B moves off at an angle of 60 ° south of east . What is the speed of ball B?

speed of ball B is 0.5 m/s

Explanation:

First the angle at which it's invliy does not matter.

Initial momentum is equall to final momentum.

M1v1 + m2v1 = m1v2 + m2v2

0.17*4 + ( 0.17*0) = 0.17*3.5 + 0.17v2

0.68 + 0= 0.595 + 0.17v2

0.68-0.595= 0.17v2

0.085 = 0.17v2

0.5 = v2

V2 = 0.5 m/s

answer; i believe the correct answer is (40,000 j) good luck

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.