A 68.0 kg diver falls from rest into a swimming pool from a height of 4.90 m. It takes 1.46 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

456.4 N

Explanation:

From conservation of energy, the potential energy is converted to kinetic energy hence

mgh=½mv²

Making v the subject then

Where g is acceleration due to gravity and h is height whike v is final velocity. Substituting 4.9m for h and 9.81 m/s² for g then

Change in momentum equals to the impulse.

Impulse, I= Ft

Change in momentum, ∆p= m(v-u)

Ft=m(v-u) making F the subject of formula then

Where F is force in Newton, t is time in seconds, m is mass of diver, v and u are the final and initial velocities respectively.

Substituting 68 kg for m, 9.8 m/s for v, 0 m/s for u since it is initially at rest and 1.46 s for t

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.